age dating rocks

what is the mineral most commonly used to age-dating proterozoic rocks?

can you please provide any online reference to the answer as well?

Zircon is the single most used mineral used for dating Proterozoic rocks, by the U-Pb system. Follow the links provided for more information.

Are Rocks Accurate for Dating?

methods of dating the earth

Why do the radiometric dating methods show that the earth is much older than I believe it to be (6000 yo)?

The dating methods show the earth is 4.5 billion years old, the methods would have to be off by nearly a FACTOR OF A MILLION for the earth to be 6000 years old!

Are the scientists/geologists retarded or am I?

Helps me!

you are the retard

8 of 12-Young Earth Evidence(Radiometric Dating)-Billy Crone

radiometric dating christian perspective

Re: flaws of evolution

dating of fossils

What is the reason for dating fossils? Not romantically of course.?

What is the logic behind the dating of fossils? Assuming that the minerals of the earth have a maximum age of 4.65 billions years, is that the age all fossils are dated as, since they have replaced all organic material with rock? And then the different strata layers seperate into different periods? Or do the fossils actually have a different range of years as in one being 700 million years or another one being 1.3 billion years. Example. Someone finds a fossil. They date it. The result comes came 4.6 billion years. But it is in the jurassic layer of earth, so they know it came later on in history and the big number only shows the age of minerals it is made of. I am only assuming, I don’t know. If someone could confirm my assumtion or correctly inform me, that would be great. thanks

The absolute ages (ie. x million years old) placed on fossils come about as a consequence of the science of Geology. Radiometric dating, such as uranium-lead, and potassium-argon, is used to get the absolute ages of suitable minerals when they are found. Only a few minerals are suitable, eg. zircon crystals and volcanic ash beds. Geologists due this because it is important for unraveling geology (the source of all our metals and petroleum).

So, for example, we know that the Jurassic Period lasted from 199.6 ± 0.6 to 145.4 ± 4.0 million years ago. And at a finer scale, we know that the Toarcian stage, within the Jurassic Period, lasted from183.0 ± 1.5 to175.6 ± 2.0 Ma. And so on for sub-stages of the Toarcian.

So when you recover a fossil from strata which is correlated to the early Toarcian, you know roughly how many millions of years old it is.

5 of 12 - Young Earth Evidence (Carbon Dating) - Billy Crone

carbon 14 dating calculator

need some help to make sure for some of my answers and explaination to others ..?

(>) is for my answers
.
1. ln(e^1.618) =
.
>1.618 is there any explaination to how to find it without using the calculator??
.
2. Sharon invest $2500 at an annual interest rate 9%. how much is tl investment worth after 10 years if the inter is compounded continuously?
.
>i use this formula A=Pe^rt, =614.9
.
3. The age of an artifact can be determined using carbon-14 dating with the equation N(t)=N(0)e^-0.00012t. What is the approximate age of an artifact if a sample reveals that it contains 34% of its original carbon-14?
.
>i didnt understand this question?!?!
.
4.log(x)1/128=-7
.
>x=2
.
5.xlog1/6=log6
.
>x=-1
.
6.ln(2x)=4ln2
.
>x=8
.
7.lnx^0.5 - 3=1
.
>?????
.
8. ln(x+1)=2ln4
.
>x=15
.
9. logx+log(x+3)=1
.
>????
.
10.3^x=5^2.3
.
>x=3.3695
.
thank you very much for your time, i really appreciate it

1) ln.x and e^x are the opposites of each other - so ln.(e^x) = x.
Just like if I said what is x * (8 / x) you know the answer is 8 because dividing by x is the opposite of multiplying by x.

2) Your answer must be wrong, as you’ve ended up with less money than she started with ($2500)! And you’d expect that after investing for 10 years at a good rate of interest (9%) you’d have more money. So that should make you think and check your method.
The formula you’ve written is wrong - you don’t need e in the equation.
I would use this equation:
A = P * r^t
P is the original investment, 2500.
r is 9% which as a multiplication factor is 1.09 (because after each year, you add 9%, so you have 109% total compared to the start, and 109% = multiply by 1.09).
t is 10 (years).
So A = 2500 * (1.09 ^ 10) = 2500 * 2.367 = $5918

3) Well, you have the formula, you just need to work out how the information in the question relates to it. N(t) is the amount of C14 left after t years. N(0) is the amount you had t the start. You’re told that N(t) is 34% of N(0), so if we divide both sides of the equation by N(0) we get:
N(t) / N(0) = 34% = 0.34 = e^-0.00012t
Take the natural log of each side:
ln0.34 = -1.0788 = ln(e^-0.00012t) = -0.00012t
So t = -1.0788 / -0.00012 = 8990 years.

4), 5) and 6) are all correct.

7) Add 3 to both sides, and remember that lnx^y = ylnx
So:
0.5 ln x = 1+3 = 4
lnx = 8
x = e^8 = 290.96

and 10) are correct.

9) remember ln(A + B) = lnA*lnB
So logx + log(x+3) = logx + logxlog3 = logx(1 + log3) = 1
I presume you’re using the convention that log means log (base 10) - if not you’ll have to correct the answers from here on
log x = 1/(1 + log3) = 1/(1 + 0.4771) = 0.6770
So x = 10^0.6770 = 4.75

Nokia Arte Carbon + Sapphire RARE !!! 100% 1:1 High End copy clone replica

dating fossils and rocks

Dating Fossils and Rocks-Evidence for a young Earth?

« Previous Page